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Proof step 2 from proof in-rem-notrem (previous step)

⊦ a ∈ bag -- b ↔ a ∈ bag, a = b

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
a ∈ bag ⊦ a = b, a ∈ bag -- b

Rule argument

Additional information

Used simplifier rules: still-in-rem: ⊦ a ∈ bag0 -- b → (a ∈ bag0 ↔ true);