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Proof step 8 from proof still-in-rem (previous step)

⊦ count(b, bag0) - 1 = 0, count(b, bag0) = 0, b ∈ bag0

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 9:
count(b, bag0) = m + 1 ⊦ count(b, bag0) = 0, m = 0, b ∈ bag0

Rule argument

spec: nat name: elim-pred-c seq: n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1 subst: [n, m] → [count(b, bag0), m]

Additional information

Used simplifier rules: n ≠ 0 ⊦ m = n - 1 ↔ n = m + 1; (elim) Used terms: count(b, bag0), m