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Proof step 5 from proof subset-emp (
previous step
)
a ∈ bag, bag ⊆ ∅ ⊦
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 6
:
⊦ a ∈ bag ↔ count(a, bag) ≠ 0
Proof step 7
:
bag ⊆ ∅ ⊦ count(a, bag) = 0
Rule argument
spec: <toplevel> name: in seq: ⊦ a ∈ bag ↔ count(a, bag) ≠ 0 subst: [bag, a] → [bag, a] flags: <all paths>
Additional information
Used terms: bag, a