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Proof step 15 from proof subset-plusplus (previous step)

count(a0, bag1) < count(a0, bag0 ++ a), ∀ a. count(a, bag0) ≤ count(a, bag1) ⊦ a0 = a

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 16:
count(a0, bag1) < count(a0, bag0), ∀ a. count(a, bag0) ≤ count(a, bag1) ⊦ a0 = a

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ a ≠ b → count(a, bag ++ b) = count(a, bag); (s)