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Proof step 1 from proof subset-trans (conclusion)
⊦ bag0 ⊆ bag1 ∧ bag1 ⊆ bag2 → bag0 ⊆ bag2
System applied rule normalize
And obtained the following new goals
Proof step 2
:
bag0 ⊆ bag1, bag1 ⊆ bag2 ⊦ bag0 ⊆ bag2
Rule argument
Additional information