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Proof step 3 from proof subset-trans (previous step)

count(a, bag2) < count(a, bag0), ∀ a. count(a, bag0) ≤ count(a, bag1), ∀ a. count(a, bag1) ≤ count(a, bag2) ⊦

User applied rule all left

And obtained the following new goals

Proof step 4:
count(a, bag2) < count(a, bag0), count(a, bag1) ≤ count(a, bag2), ∀ a. count(a, bag1) ≤ count(a, bag2), ∀ a. count(a, bag0) ≤ count(a, bag1) ⊦

Rule argument

pos: left 3 terms: a abort: F discard: F computed: T

Additional information

Used terms: a