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Proof step 25 from proof nextli-lemma (previous step)

lfgen(0)(0) = [], m0 < n0, m0 < n1, n1 ≤ n0, ∀ n. lfgen(n)(0) = [] ∧ (∀ m. m < n → lfgen(n)(m + 1) = nextli(lfgen(n)(m))) ⊦ lfgen(n1)(m0 + 1) = lfgen(n0)(m0 + 1), m0 ≤ n0 ∧ m0 ≤ n1

User applied rule case distinction

And closed the goal!

Rule argument

pos: right 2

Additional information

Used simplifier rules: ⊦ m ≤ n ↔ ¬ n < m; (ss)% ⊦ m < n → ¬ n < m; (s)