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Proof step 25 from proof nextl-lemma (previous step)

lfgen(0)(0) = nextl(0, a), lfgen(n1)(m0) = lfgen(n0)(m0), m0 < n1, m0 < n0, n1 ≤ n0, ∀ n. lfgen(n)(0) = nextl(0, a) ∧ (∀ m. m < n → lfgen(n)(m + 1) = nextl(m + 1, lfgen(n)(m).last)) ⊦ lfgen(n1)(m0 + 1) = lfgen(n0)(m0 + 1)

User applied rule all left

And obtained the following new goals

Proof step 26:
lfgen(n1)(m0) = lfgen(n0)(m0), lfgen(0)(0) = nextl(0, a), lfgen(n1)(0) = nextl(0, a), m0 < n0, m0 < n1, n1 ≤ n0, ∀ n. lfgen(n)(0) = nextl(0, a) ∧ (∀ m. m < n → lfgen(n)(m + 1) = nextl(m + 1, lfgen(n)(m).last)), ∀ m. m < n1 → lfgen(n1)(m + 1) = nextl(m + 1, lfgen(n1)(m).last) ⊦ lfgen(n1)(m0 + 1) = lfgen(n0)(m0 + 1)

Rule argument

pos: left 6 terms: n1 abort: F discard: F computed: F

Additional information

Used terms: n1