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Proof step 2 from proof weakmon-lem (previous step)

∀ n. ii(n) ≤ ii(n + 1) ⊦ ∀ n. ∃ m. ii(m) ≥ n, ∃ n. ∀ m. m ≥ n → ii(m) = ii(n)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
∀ n. ii(n) ≤ ii(n + 1) ⊦ ∃ n0. ∀ m. n0 ≤ m → ii(m) = ii(n0), ∃ m. n ≤ ii(m)

Rule argument

Additional information

Used simplifier rules: ⊦ n ≥ m ↔ m ≤ n; (s)