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Proof step 5 from proof weakmon-lem (previous step)

∀ m. ii(m) ≤ ii(m0), ∀ n. ii(n) ≤ ii(n + 1) ⊦ ∃ n0. ∀ m. n0 ≤ m → ii(m) = ii(n0), ∃ m. n ≤ ii(m)

User applied rule exists right

And obtained the following new goals

Proof step 6:
∀ n. ii(n) ≤ ii(n + 1), ∀ m. ii(m) ≤ ii(m0) ⊦ ∀ m. m0 ≤ m → ii(m) = ii(m0), ∃ m. n ≤ ii(m)

Rule argument

pos: right 1 terms: m0 abort: F discard: T computed: F

Additional information

Used terms: m0