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Proof step 7 from proof absa (previous step)

i < 0, i + j < 0 ⊦ 0 = abs(j) + j, 0 < j

Heuristic weak cut applied rule cut formula

And closed the goal!

Rule argument

fma: j < 0

Additional information

Used simplifier rules: Abs-neg: ⊦ j < 0 → abs(j) = 0 - j;%sub-add-01: ⊦ i + (j - i0) = i + j - i0;%sub-sub-03: ⊦ i - i = 0;%Abs-pos: ⊦ ¬ j < 0 → abs(j) = j;% ⊦ i + i = 0 ↔ i = 0; (s)% ⊦ ¬ i < j → (i = j ↔ ¬ j < i); (ss)%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2% ⊦ 0 + i = i; (s) Used formulas: j < 0