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Proof step 2 from proof int-simp-02 (previous step)

i2 < i3, i ≤ i1 ⊦ i + i2 = i1 + i3 ↔ false

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: int-simp-03: ⊦ i < i1 ∧ i2 ≤ i3 → (i + i2 = i1 + i3 ↔ false);%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2