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Proof step 2 from proof int-simp-06 (previous step)

i < i1, i2 ≤ i3 ⊦ i1 + i3 < i + i2 ↔ false

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
i < i1, i1 + i3 < i + i2 ⊦ i3 < i2

Rule argument

Additional information

Used simplifier rules: le-def: ⊦ i ≤ j ↔ ¬ j < i;