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Proof step 2 from proof int-simp-07 (previous step)

i ≤ i1, i2 ≤ i3 ⊦ i1 + i3 < i + i2 ↔ false

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: le-def: ⊦ i ≤ j ↔ ¬ j < i;%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2% ⊦ ¬ i < j ∧ ¬ i0 < j0 → ¬ i + i0 < j + j0; (s)