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Proof step 2 from proof le-add-01 (previous step)

i + j ≤ i0, j ≥ 0, j0 ≥ 0 ⊦ i - j0 ≤ i0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
j0 + i0 < i ⊦ j0 < 0, j < 0, i0 < i + j

Rule argument

Additional information

Used simplifier rules: ge-def: ⊦ i ≥ j ↔ ¬ i < j;%le-def: ⊦ i ≤ j ↔ ¬ j < i;%sub-le: ⊦ i - j ≤ i0 ↔ i ≤ j + i0;