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Proof step 2 from proof le-add-02 (previous step)

i + j0 ≤ i0, j0 ≥ 0 ⊦ i ≤ i0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
i0 < i ⊦ j0 < 0, i0 < i + j0

Rule argument

Additional information

Used simplifier rules: ge-def: ⊦ i ≥ j ↔ ¬ i < j;%le-def: ⊦ i ≤ j ↔ ¬ j < i;