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Proof step 5 from proof le-add-08 (previous step)

i0 + j < i1 + i2, 0 < i, 0 ≤ i0, i0 + i1 + i2 + i ≤ j, i1 + i2 + i ≤ j ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ i < j ↔ ¬ j ≤ i
Proof step 7:
0 < i, i1 + i2 + i ≤ j, i0 + i1 + i2 + i ≤ j, 0 ≤ i0 ⊦ i1 + i2 ≤ i0 + j

Rule argument

spec: <toplevel> name: lels seq: ⊦ i < j ↔ ¬ j ≤ i subst: [j, i] → [i1 + i2, i0 + j] flags: <all paths>

Additional information

Used terms: i1 + i2, i0 + j