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Proof step 2 from proof lstwo-01 (previous step)

0 ≤ i ⊦ i < 2 ↔ i = 1, i = 0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: le-def: ⊦ i ≤ j ↔ ¬ j < i;% ⊦ 0 < j → (j < 2 ↔ j = 1); (s)% ⊦ ¬ i < j → (i = j ↔ ¬ j < i); (ss)