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Proof step 2 from proof mone-07 (previous step)

⊦ i + 1 = 0, ~1 ≤ i ↔ 0 ≤ i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ ¬ i < ~1 ↔ ¬ i < 0, ~1 = i

Rule argument

Additional information

Used simplifier rules: le-def: ⊦ i ≤ j ↔ ¬ j < i;%numadd-01: ⊦ (* j) = i0 + (* j0) ↔ j - j0 = i0;%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2