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Proof step 2 from proof mone-neg (previous step)

i + j = ~1, 0 ≤ i, 0 ≤ j ⊦

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: not-mone: ⊦ 0 ≤ j ∧ 0 ≤ i → i + j ≠ ~1;%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2