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Proof step 3 from proof ple-01 (previous step)

0 < j ⊦ j0 < i0, 0 + i0 < j + j0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
0 < j ⊦ j0 < i0, i0 < j + j0

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j;%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2% ⊦ 0 + i = i; (s)