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Proof step 4 from proof zero-not (previous step)

i + i0 = 0, abs(i) < j, i < 0 ⊦ abs(i0) < j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
i + i0 = 0, 0 < i + j, i < 0 ⊦ abs(i0) < j

Rule argument

Additional information

Used simplifier rules: abs-08: ⊦ i < 0 → abs(i) = ~ i;%Minus-def: ⊦ ~ i = 0 - i;%sub-ls: ⊦ i - j < i0 ↔ i < j + i0;%forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j;%forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0;%zero-gels-01: ⊦ i < 0 ∧ 0 ≤ j → i < j;