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Proof step 2 from proof ls-rec (previous step)

⊦ i < j ↔ i < j -1, i = j -1

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: pred: ⊦ i = j -1 ↔ i +1 = j;%ls-pred: ⊦ i < j -1 ↔ i +1 < j;%ls-succ-04: ⊦ i < j → (i +1 < j ↔ i +1 ≠ j);%l: ⊦ i < j ↔ ¬(i = j ∨ j < i);%succ: ⊦ i ≠ i +1;%ls: ⊦ ¬ i +1 < i;%trans: ⊦ i < j ∧ j < j0 → i < j0;