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Proof step 16 from proof lst-02 (previous step)

0 < i +1 ⊦ i = ~1, i = 0, i < 0, 0 < i

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 17:
⊦ i < j ↔ i +1 = j ∨ i +1 < j
Proof step 18:
0 +1 = i +1 ∨ 0 +1 < i +1 ⊦ i = 0, i = ~1, 0 < i, i < 0

Rule argument

spec: <toplevel> name: lsrec seq: ⊦ i < j ↔ i +1 = j ∨ i +1 < j subst: [j, i] → [i +1, 0] flags: <all paths>

Additional information

Used terms: i +1, 0