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Proof step 2 from proof numeral-01 (previous step)

⊦ i +1 < j ↔ i < j -1

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 3:
⊦ i = j -1 ↔ j = i +1
Proof step 4:
j = i0 +1 ⊦ i +1 < j ↔ i < i0

Rule argument

spec: <toplevel> name: elim-pred seq: ⊦ i = j -1 ↔ j = i +1 subst: [j, i] → [j, i0] flags: <rotated> <all paths>

Additional information

Used terms: j, i0