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Proof step 12 from proof add-in (previous step)

i1 -1 + j = i1 -1 + i0, ∀ j, i0. i1 + j = i1 + i0 → j = i0 ⊦ j = i0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: add-pred: ⊦ i + j -1 = (i + j)-1;%add-a: ⊦ i + j + i0 = (i + j) + i0;%add-c: ⊦ i + j = j + i;% ⊦ i -1 = j -1 ↔ i = j; (s)