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Proof step 8 from proof ls (previous step)

∀ i. i + j0 < j0 ↔ i < 0 ⊦ i + j0 -1 < j0 -1 ↔ i < 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
∀ i. i + j0 < j0 ↔ i < 0 ⊦ i + j0 < j0 ↔ i < 0

Rule argument

Additional information

Used simplifier rules: add-pred: ⊦ i + j -1 = (i + j)-1;%add-a: ⊦ i + j + i0 = (i + j) + i0;% ⊦ i -1 < j -1 ↔ i < j; (s)