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Proof step 4 from proof lst-02 (previous step)

i < j + 0 ⊦ i < j0 + 0, j0 < j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
i < j ⊦ j0 < j, i < j0

Rule argument

Additional information

Used simplifier rules: add-zero: ⊦ i + 0 = i;%add-a: ⊦ i + j + i0 = (i + j) + i0;%add-c: ⊦ i + j = j + i;