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Proof step 7 from proof lst-02 (previous step)

i < j + i1 +1, ∀ i, j, j0. i < j + i1 → j0 < j ∨ i < j0 + i1 ⊦ i < j0 + i1 +1, j0 < j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
i < j + i1 + 1, ∀ i, j, j0. i < j + i1 → j0 < j ∨ i < j0 + i1 ⊦ j0 < j, i < j0 + i1 + 1

Rule argument

Additional information

Used simplifier rules: succ-01: ⊦ i +1 = i + 1;