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Proof step 2 from proof lst-04 (previous step)

i + j < i0, j0 < j ⊦ i + j0 < i0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ls-01: ⊦ i + j < i + i0 ↔ j < i0;%add-a: ⊦ i + j + i0 = (i + j) + i0;%add-c: ⊦ i + j = j + i;% ⊦ i < j → ¬ j < i; (s)%lf-07: ⊦ ¬ i < i0 ∧ j < i0 → j < i; (forward) from specification int-basic1