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Proof step 2 from proof lst-05 (previous step)

i < 0, j < j0 ⊦ i + j < j0 + i0, i0 < 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
j < j0, i < 0, i < i0 ⊦ i0 < 0, i + j < j0 + i0

Rule argument

Additional information

Used simplifier rules: lf-07: ⊦ ¬ i < i0 ∧ j < i0 → j < i; (forward) from specification int-basic1