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Proof step 3 from proof nls (previous step)

i + i0 < j + j0 ⊦ i < j, i0 < j0

User applied rule cut formula

And obtained the following new goals

Proof step 4:
i + i0 < j + j0 ⊦ i = j, i0 < j0, i < j

Rule argument

fma: i = j

Additional information

Used simplifier rules: ls-01: ⊦ i + j < i + i0 ↔ j < i0;%add-a: ⊦ i + j + i0 = (i + j) + i0;%add-c: ⊦ i + j = j + i;% ⊦ ¬ i < i; (s)%lf-07: ⊦ ¬ i < i0 ∧ j < i0 → j < i; (forward) from specification int-basic1%lf-04: ⊦ ¬ j < i ∧ j < i0 → i < i0; (forward) from specification int-basic1 Used formulas: i = j