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Proof step 7 from proof pls (previous step)

i1 < j + 1, i0 < j0, j + 1 < i1 ∧ i1 < j0 → i1 + j + 1 < j0 + i1, ∀ i0, j0, j. i0 < j0 ∧ i1 < j → i1 + i0 < j + j0 ⊦ i0 + i1 < (j + j0) + 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information