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Proof step 2 from proof zero-04 (previous step)

0 = i + j, 0 < i, 0 < j ⊦

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ls: ⊦ i + j < j ↔ i < 0;%add-a: ⊦ i + j + i0 = (i + j) + i0;%add-c: ⊦ i + j = j + i;% ⊦ i < j → ¬ j < i; (s)%lf-03: ⊦ i < j ∧ i = i0 → i0 < j; (forward) from specification int-basic1