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Proof step 2 from proof abs-01 (previous step)

⊦ abs(i / abs(j)) = abs(i / j), j = 0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: abs: j ≠ 0 ⊦ abs(i / j) = abs(i) / abs(j);% ⊦ abs(abs(i)) = abs(i); (s)% ⊦ abs(i) = 0 ↔ i = 0; (s)