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Proof step 5 from proof abs-shift (previous step)

i % j < 0 ⊦ abs(i % j) = abs(i) % abs(j), j = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
i % j < 0 ⊦ i % j + abs(i) % abs(j) = 0, j = 0

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs% ⊦ ~ i = j ↔ i + j = 0; (s)% ⊦ i < 0 → abs(i) = ~ i; (s)