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Proof step 10 from proof div-add-nosucc (previous step)

j0 * j + j = i0 + 1, i0 / j = (j - 1) / j + j0, 0 < j, 1 < j, 0 ≤ j0 ⊦ i0 / j = j0, j = 0

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 11:
j0 * j + j = i0 + 1, i0 / j = i1 / j + j0, j = i1 + 1, 1 < j, 0 < j, 0 ≤ j0 ⊦ i0 / j = j0, j = 0

Rule argument

spec: int-abs name: elim-sub seq: ⊦ i0 = i - j ↔ i = i0 + j subst: [i, j, i0] → [j, 1, i]

Additional information

Used simplifier rules: ⊦ i0 = i - j ↔ i = i0 + j; (elim) Used terms: j, 1, i