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Proof step 2 from proof div-add-rew (previous step)

0 < j, 0 ≤ i, 0 ≤ i0 ⊦ (i + i0) / j = i / j + i0 / j + (i % j + i0 % j) / j

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: add-div-mult: ⊦ 0 ≤ i ∧ 0 ≤ i0 ∧ 0 < j → (i / j + i0 / j) + (i % j + i0 % j) / j = (i + i0) / j;%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2