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Proof step 1 from proof div-add1-negpos-pos (conclusion)

⊦ i % j = 0 ∧ 0 ≤ i + i0 ∧ i < 0 ∧ 0 ≤ i0 ∧ 0 < j → (i + i0) / j = i / j + i0 / j

System applied rule normalize

And obtained the following new goals

Proof step 2:
i % j = 0, i < 0, 0 < j, 0 ≤ i + i0, 0 ≤ i0 ⊦ (i + i0) / j = i / j + i0 / j

Rule argument

Additional information