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Proof step 11 from proof div-div (previous step)

(i / abs(j)) / abs(j0) = i / (abs(j) * abs(j0)), 0 ≤ i ⊦ (i / j) / j0 = i / (j * j0), j = 0, j0 = 0, j < 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
(i / j) / abs(j0) = i / (j * abs(j0)), 0 < j, 0 ≤ i ⊦ (i / j) / j0 = i / (j * j0), j0 = 0

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs% ⊦ i < j → ¬ j < i; (s)% ⊦ ¬ i < j → (i = j ↔ ¬ j < i); (ss)% ⊦ ¬ j < 0 → abs(j) = j; (s)