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Proof step 21 from proof div-div (previous step)

(i / j) / abs(j0) = i / (j * abs(j0)), i < 0, 0 < j ⊦ (i / j) / j0 = i / (j * j0), j0 = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 22:
⊦ i * j = j * i
Proof step 23:
(i / j) / abs(j0) = i / (abs(j0) * j), 0 < j, i < 0 ⊦ (i / j) / j0 = i / (j * j0), j0 = 0

Rule argument

spec: int-mult name: commutativity seq: ⊦ i * j = j * i subst: [j, i] → [abs(j0), j] flags: <all paths>

Additional information

Used terms: abs(j0), j