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Proof step 2 from proof div-elim (previous step)

0 < j, 0 < i ⊦ i0 = i / j ∧ j0 = i % j ↔ i = i0 * j + j0 ∧ 0 ≤ j0 ∧ j0 < j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
0 < i, 0 < j ⊦ i0 = i / j ∧ j0 = i % j ↔ i = i0 * j + j0 ∧ 0 ≤ j0 ∧ j0 < j

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs