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Proof step 6 from proof div-elim2 (previous step)

i0 = i / j ∧ j0 = i % j ↔ i = j0 + i0 * j ∧ j0 ≤ 0 ∧ 0 < j + j0, i < 0, 0 < j ⊦ i0 = i / j ∧ j0 = i % j ↔ i = i0 * j + j0 ∧ j0 ≤ 0 ∧ abs(j0) < j

User applied rule case distinction

And closed the goal!

Rule argument

pos: right 1

Additional information

Used simplifier rules: divmod-rew: j ≠ 0 ⊦ i / j * j + i % j = i;%add-c: ⊦ i + j = j + i; from specification int-basic2% ⊦ i ≤ 0 ∧ 0 ≤ j → i ≤ j; (s)% ⊦ i < j ↔ ¬ j ≤ i; (ss)%forward-lels: ⊦ i ≤ j ∧ j < j0 → i < j0; (forward) from specification int-abs%forward-le-04: ⊦ j ≤ i ∧ i ≤ 0 → j ≤ 0; (forward) from specification int-abs%forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs% ⊦ i + j < j ↔ i < 0; (s)%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2% ⊦ i < 0 → abs(i) = ~ i; (s)% ⊦ ~ i < j ↔ 0 < j + i; (s)% ⊦ i ≤ j → ¬ j < i; (s)% ⊦ i + 0 = i; (s)%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%commutativity: ⊦ i * j = j * i; from specification int-mult% ⊦ ¬ abs(i) < 0; (s)%forward-le: ⊦ i ≤ j ∧ 0 < i → 0 < j; (forward) from specification int-abs%forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs% ⊦ 0 < abs(i) ↔ i ≠ 0; (s)% ⊦ 0 < i → i1 < i1 + i; (s)% ⊦ i ≠ j → (i ≤ j ↔ i < j); (s)% ⊦ i ≤ ~ j ↔ i + j ≤ 0; (s)% ⊦ i < j → (j ≤ i ↔ false); (as)