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Proof step 15 from proof div-eq-same-01 (previous step)

i = i0 * j + j0, i0 = i, i < 0, 0 < j, abs(j0) < j, j0 ≤ 0, i0 ≤ 0 ⊦ j = 1, j = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 16:
i = i * j + j0, abs(j0) < j, 0 < j, i < 0, j0 < j, j0 ≤ 0 ⊦ j = 0, j = 1

Rule argument

Additional information

Used simplifier rules: forward-le-04: ⊦ j ≤ i ∧ i ≤ 0 → j ≤ 0; (forward) from specification int-abs%forward-lels: ⊦ i ≤ j ∧ j < j0 → i < j0; (forward) from specification int-abs% ⊦ i < 0 ∧ 0 ≤ j → i ≤ j; (s)