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Proof step 26 from proof div-eq-same-01 (previous step)

i = i0 * j + j0, i0 = i, j0 < j, 0 < j, 0 ≤ j0, 0 ≤ i0, 0 ≤ i ⊦ i = 0, j = 1, j = 0, j < 0 ∧ i < 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 27:
i = i * j + j0, 0 < i, j0 < j, 0 < j, 0 ≤ j0 ⊦ i = 0, j = 1, j = 0

Rule argument

Additional information

Used simplifier rules: forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs%forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs% ⊦ i < j → ¬ j < i; (s)% ⊦ i ≠ j → (i ≤ j ↔ i < j); (s)% ⊦ i ≤ 0 ∧ 0 ≤ j → i ≤ j; (s)