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Proof step 6 from proof div-eq-zero-01 (previous step)

⊦ i / j = 0 ↔ abs(i) < abs(j), 0 = j, 0 < i ∧ 0 < j

User applied rule cut formula

And obtained the following new goals

Proof step 7:
i < 0 ⊦ i / j = 0 ↔ abs(i) < abs(j), 0 = j, 0 < i ∧ 0 < j
Proof step 27:
⊦ i / j = 0 ↔ abs(i) < abs(j), 0 = j, i < 0, 0 < i ∧ 0 < j

Rule argument

fma: i < 0

Additional information

Used formulas: i < 0