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Proof step 2 from proof div-est-denom-pos (previous step)

0 < j, i0 ≤ i / j0, j ≤ j0, 0 ≤ i ⊦ i0 ≤ i / j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
i / j < i0, 0 < j0, 0 < j, i / j < i / j0, j ≤ j0, i0 ≤ i / j0, 0 ≤ i ⊦

Rule argument

Additional information

Used simplifier rules: forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs%forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%forward-lsle: ⊦ i < j ∧ j ≤ j0 → i < j0; (forward) from specification int-abs% ⊦ i ≤ j ↔ ¬ j < i; (ss)