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Proof step 2 from proof div-est-num (previous step)

i0 / j < j0, 0 < j, i ≤ i0 ⊦ i / j < j0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
i0 / j < j0, 0 < j, i0 / j < i / j, i ≤ i0, j0 ≤ i / j ⊦

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%forward-lsle: ⊦ i < j ∧ j ≤ j0 → i < j0; (forward) from specification int-abs% ⊦ i < j ↔ ¬ j ≤ i; (ss)