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Proof step 16 from proof div-le-pos (previous step)

i0 = i2 * j + j2, i0 < 0, j0 < j, abs(j1) < j, i2 < j0, 0 < j, i1 < j, j1 < j, i2 < i1, i2 < 0, i1 * j + j1 < 0, abs(j2) < j, i1 ≤ 0, j1 ≤ 0, i1 * j + j1 ≤ i0, j0 ≤ i1, j0 ≤ 0, j2 ≤ 0, i2 ≤ 0 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%commutativity: ⊦ i * j = j * i; from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult% ⊦ i < 0 ∧ j0 < j ∧ 0 < j → i * j + j0 < 0; (s)%forward-le-04: ⊦ j ≤ i ∧ i ≤ 0 → j ≤ 0; (forward) from specification int-abs%forward-lels: ⊦ i ≤ j ∧ j < j0 → i < j0; (forward) from specification int-abs%forward-lsle: ⊦ i < j ∧ j ≤ j0 → i < j0; (forward) from specification int-abs%forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs% ⊦ i < 0 ∧ 0 ≤ j → i ≤ j; (s)