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Proof step 2 from proof div-le-same-neg (previous step)

i < 0, 0 < j ⊦ i / j ≤ i ↔ i = 0 ∨ j = 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
0 < j, i < 0 ⊦ i / j ≤ i ↔ i = 0 ∨ j = 1

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs